The rule to remember is, Every element of a partition has the same rank as the original noun.
So, every element of a partition of a table is a table. Possibly 1 (or 0) rows, but still a table. Henry Rich > -----Original Message----- > From: [EMAIL PROTECTED] > [mailto:[EMAIL PROTECTED] On Behalf Of Don Guinn > Sent: Sunday, October 19, 2008 8:58 AM > To: Programming forum > Subject: [Jprogramming] Cut Question > > Playing with J for C and got to "Apply On Specified > Partitions: Dyad u;.1 > and u;.2". Replaced the < with +/ and it didn't sum the rows. > After looking > at the result a little more closely I discovered that each > cell contained a > table instead of a row. > (0 1 1;1 0 0 1) <;.1 i. 3 4 > +------+--+ > |4 5 6 |7 | > +------+--+ > |8 9 10|11| > +------+--+ > (0 1 1;1 0 0 1) (<@$);.1 i. 3 4 > +---+---+ > |1 3|1 1| > +---+---+ > |1 3|1 1| > +---+---+ > > I can't figure out why. > > Also, in the Dictionary for Cut it describes the rank as "_ > 1/2 _". What > does the "1/2" mean? Needless to say, I still have a long way > go to fully > understand Cut. > ---------------------------------------------------------------------- > For information about J forums see > http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
