(1 + *)/"0 1~ i.3 1 1 1 1 2 3 1 3 5 2008/10/30 June Kim <[EMAIL PROTECTED]>
> */~ i.3 > 0 0 0 > 0 1 2 > 0 2 4 > > Yes. > > (1 + *)/~ i.3 > 1 2 5 > > What? > > I was surprised since I originally thought the result of (1 + *)/ > should be instead: > > 1 1 1 > 1 2 3 > 1 3 5 > > >From the dictionary: > > "In general, each cell of x is applied to the entire of y" > > So my guess of the result was like the concatenation of, > > 0 (1+*) i. 3 > 1 (1+*) i. 3 > 2 (1+*) i. 3 > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm > -- Björn Helgason, Verkfræðingur Fugl&Fiskur ehf, Þerneyjarsundi 23, Hraunborgum Po Box 127,801 Selfoss , t-póst: [EMAIL PROTECTED] gsm: +3546985532 Landslags og skrúðgarðagerð, gröfuþjónusta http://groups.google.com/group/J-Programming Tæknikunnátta höndlar hið flókna, sköpunargáfa er meistari einfaldleikans góður kennari getur stigið á tær án þess að glansinn fari af skónum /|_ .-----------------------------------. ,' .\ / | Með léttri lund verður | ,--' _,' | Dagurinn í dag | / / | Enn betri en gærdagurinn | ( -. | `-----------------------------------' | ) | (\_ _/) (`-. '--.) (='.'=) `. )----' (")_(")
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