Also:
(1 + *)"0/~ i.3
1 1 1
1 2 3
1 3 5
NB. foo"0/ i. n should cover it.
Björn Helgason wrote:
(1 + *)/"0 1~ i.3
1 1 1
1 2 3
1 3 5
2008/10/30 June Kim <[EMAIL PROTECTED]>
*/~ i.3
0 0 0
0 1 2
0 2 4
Yes.
(1 + *)/~ i.3
1 2 5
What?
I was surprised since I originally thought the result of (1 + *)/
should be instead:
1 1 1
1 2 3
1 3 5
>From the dictionary:
"In general, each cell of x is applied to the entire of y"
So my guess of the result was like the concatenation of,
0 (1+*) i. 3
1 (1+*) i. 3
2 (1+*) i. 3
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|\/| Randy A MacDonald | APL: If you can say it, it's done.. (ram)
|/\| ramacd <at> nbnet.nb.ca |
|\ | | The only real problem with APL is that
BSc(Math) UNBF'83 | it is "still ahead of its time."
Sapere Aude | - Morten Kromberg
Natural Born APL'er |
-----------------------------------------------------(INTP)----{ gnat }-
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