f0=: 4 : '(I.x)</.y'
f1=: 4 : '((i.#y) e. +/\0,x) <;.1 y'
x=: 1+1e4 [EMAIL PROTECTED] 100
y=: t {~ (+/x) [EMAIL PROTECTED] #t=. 'barack obama'
x (f0 -: f1) y
1
ts=: 6!:2 , 7!:[EMAIL PROTECTED]
ts 'x f0 y'
0.0700156 1.09591e7
ts 'x f1 y'
0.00778395 4.20992e6
----- Original Message -----
From: [EMAIL PROTECTED]
Date: Tuesday, November 4, 2008 20:47
Subject: [Jprogramming] cut on length
To: [email protected]
> Hello,
>
> I've been using J for a while, and to my great shame, I can't
> wrap my
> head around this one. This is supposed to be easy. Maybe I'm
> just tired.
>
> Excuses aside, this is what I want to do.
>
> Given vector "lengths" containing n integers, and variable "tobecut",
> either a vector of characters or numbers. And given that
> (+/lengths) =
> #tobecut.
>
> I want a verb v which will cut "tobecut" by length.
>
> For example:
>
> lengths =: 4 2 5
> tobecut =: 'abcdefghijk'
>
> lengths v tobecut
> +----+--+-----+
> |abcd|ef|ghijk|
> +----+--+-----+
>
> Of course, the fastest, the better.
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