The explanation is that <;.0 is not supported by special code
but x</.y and <;.n for n e. _1 _2 1 2 are.



----- Original Message -----
From: Oleg Kobchenko <[EMAIL PROTECTED]>
Date: Wednesday, November 5, 2008 8:54
Subject: Re: [Jprogramming] cut on length
To: Programming forum <[email protected]>

> At the same time it was puzzling how the most
> straightforward method--passing concrete indices
> and lengths--did not produce a good speed.
> 
>     f3=: (,:"0~ 0,+/[EMAIL PROTECTED]:)@[ <;.0 ]
>     f3a=: <;.0
> 
>     z=. (,:"0~ 0,+/[EMAIL PROTECTED]:) x
> 
> 
>     x (f0 -: f3) y
> 1
>     z ((x f0 ]) -: f3a) y
> 1
> 
>    3 ts 'x f0 y'
> 0.0341443 1.09757e7
>    3 ts 'x f1 y'
> 0.00830281 4.22656e6
>    3 ts 'x f3 y'
> 0.0155314 5.07117e6
>    3 ts 'z f3a y'
> 0.0116746 4.94016e6
> 
> 
> 
> > From: Roger Hui <[EMAIL PROTECTED]>
> > 
> > It has been a long quest in APL/J to make
> > x e. y  as fast as  1 x1}y1 .  The quest continues.
> > 
> > I must say that I like Brian Schott's solution (I.x)> the 
> best.  The implementation should reward concise
> > solutions and I'll see if I can make that solution faster.
> > 
> > 
> > ----- Original Message -----
> > From: "Sherlock, Ric" 
> > Date: Tuesday, November 4, 2008 22:57
> > Subject: RE: [Jprogramming] cut on length
> > To: Programming forum 
> > 
> > > ---Roger Hui wrote:
> > > >    f0=: 4 : '(I.x)> > >    
> f1=: 4 : '((i.#y) e. +/\0,x) <;.1 y'
> > > >
> > > >    x=: 1+1e4 [EMAIL PROTECTED] 100
> > > >    y=: t {~ (+/x) [EMAIL PROTECTED] #t=. 'barack obama'
> > > >
> > > >    x (f0 -: f1) y
> > > > 1
> > > >    ts=: 6!:2 , 7!:[EMAIL PROTECTED]
> > > >
> > > >    ts 'x f0 y'
> > > > 0.0700156 1.09591e7
> > > >    ts 'x f1 y'
> > > > 0.00778395 4.20992e6
> > > 
> > > When I saw Brian's solution I wasn't going to post mine - 
> his 
> > > was so much simpler (BTW I have only used monadic I. to turn 
> a 
> > > boolean into an index of 1s and hadn't realised what it did 
> with 
> > > integers). Roger's post prompted me to time mine and the 
> result 
> > > surprised me.
> > > 
> > >    f2=: 4 : '(1 (<:+/\x)} (#y)$0) <;.2 y'
> > >    x (f1 -: f2) y
> > > 1
> > >   50 ts 'x f0 y'
> > > 0.030942459167 10976256
> > >   50 ts 'x f1 y'
> > > 0.0077791269561 4227072
> > >   50 ts 'x f2 y'
> > > 0.0060425808308 2654272
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