100<....@%~+/(10^101x)*%!i.75x 2718281828459045235360287471352662497757247093699959574966967627724076630353 547594571382178525166427
gives the first 100 digits of ^1 For N digits, find k such that (10^N)<!k and determine 100<....@%~+/(10^x:1+N)*%!i.x:k The first 1e5 digits can be found at http://www.mu.org/~doug/exp/100000.html R.E. Boss ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
