That is really a significant improvement. I saw only 20% improvement over
the whole process where the random number generation was only a small part.
I just did it the first and easiest way I thought of. Key is probably not a
very efficient way to count the occurrences, but it is easy.

On Sun, Apr 25, 2010 at 5:29 PM, Roger Hui <[email protected]> wrote:

> There are other situations where the expression I suggested
> is much more economical than the one you used.  For example:
>
>   ts=: 6!:2 , 7!:2...@]
>
>   10 ts '1e6 ?...@$ 2'
> 0.0029846 1.04934e6
>   10 ts '?1e6 $ 2'
> 0.0132888 5.24352e6
>
> i.e. factor of 4 in time, factor of 5 in space.
>
>
>
> ----- Original Message -----
> From: Don Guinn <[email protected]>
> Date: Sunday, April 25, 2010 7:53
> Subject: Re: [Jprogramming] Random Numbers with interation
> To: Programming forum <[email protected]>
>
> > True. There is a lot that could be done to make it faster. But
> > it was so
> > much faster I didn't bother. And as you say, if you can't half
> > the time,
> > it's not worth doing. But I did try it. Looks like maybe 20% faster
> >
> > On Sun, Apr 25, 2010 at 9:18 AM, Roger Hui <[email protected]> wrote:
> >
> > > Slightly more economical to do 1...@#50 or 1...@$50
> > > instead of ?1e6#50 .
> > >
> > >
> > >
> > > ----- Original Message -----
> > > From: Don Guinn <[email protected]>
> > > Date: Sunday, April 25, 2010 5:57
> > > Subject: Re: [Jprogramming] Random Numbers with interation
> > > To: Programming forum <[email protected]>
> > >
> > > > How about 0.07 seconds.
> > > >
> > > >    6!:2 '(1!:2&2)|."1]10{.\:~(>:~.z),.~
> > #/.~z=.?1e6#50'> > 15 20400
> > > >  8 20340
> > > > 46 20287
> > > > 13 20278
> > > > 33 20249
> > > > 39 20220
> > > > 18 20219
> > > > 29 20206
> > > > 25 20197
> > > >  9 20166
> > > > 0.0658392
> > > >
> > > > On Sun, Apr 25, 2010 at 7:36 AM, smandula
> > > > <[email protected]> wrote:
> > > >
> > > > >
> > > > > Thank you kindly for your reply.
> > > > > The statement of one million is an example, could be
> > > > 1,000  or 50,000
> > > > > iterations.
> > > > > The random numbers being tested could be 1 to 50, or 1 to 100
> > > > >
> > > > > I have a basic program whereby I enter the maximum iterations,
> > > > in the
> > > > > example 1,000,000
> > > > > and a time clock starts, and a counter starts counting up to
> > > > the required
> > > > > 1,000,000 intervals.
> > > > >
> > > > > Once, done the time duration shows, in my case 17 minutes, and
> > > > a list of 10
> > > > > highest occurrences
> > > > > for these random numbers. i.e.
> > > > > number 29     occurrences  204,984
> > > > > number 26     occurrences  204,855
> > > > > number 40     occurrences  204,732
> > > > > number 17     occurrences  204,629
> > > > > Number  1     occurrences  204,480
> > > > >
> > > > > I would appreciate any input from the forum, especially for
> > > > faster times
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