Residue gives the same. 5#:0j1+i.9 0j1 1j1 2j1 _2j1 _1j1 0j1 1j1 2j1 _2j1 0 5#:0j1+i.9 0 0j1 0 1j1 0 2j1 1 _2j1 1 _1j1 1 0j1 1 1j1 1 2j1 2 _2j1 5|0j1+i.9 0j1 1j1 2j1 _2j1 _1j1 0j1 1j1 2j1 _2j1
On Mon, Aug 16, 2010 at 1:21 PM, Bo Jacoby <bojac...@yahoo.dk> wrote: > I get another result. > 5#:0j1+i.9 > 0j1 1j1 2j1 3j1 0 0j1 1j1 2j1 3j1 > > > --- Den man 16/8/10 skrev Raul Miller <rauldmil...@gmail.com>: > > > Fra: Raul Miller <rauldmil...@gmail.com> > > Emne: [Jprogramming] what is happening here? > > Til: "Programming forum" <programming@jsoftware.com> > > Dato: mandag 16. august 2010 18.41 > > Does this make sense? > > > > 5#:i.9 > > 0 1 2 3 4 0 1 2 3 > > 5#:0j1+i.9 > > 0j1 1j1 2j1 _2j1 _1j1 0j1 1j1 2j1 _2j1 > > > > -- > > Raul > > ---------------------------------------------------------------------- > > For information about J forums see http://www.jsoftware.com/forums.htm > > > > > > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm > ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
