isboxed =: 0 < l...@{.

Works for 0$a: as well. I definitely think this little addition ultimately 
makes the theory simpler.

Marshall

-----Original Message-----
From: [email protected] 
[mailto:[email protected]] On Behalf Of Kip Murray
Sent: Sunday, October 10, 2010 7:30 PM
To: Programming forum
Subject: Re: [Jprogramming] Sets

It's a valid question.  There were technical reasons for putting a: at the end 
of every set. One was, I wanted every set to satisfy

isboxed =: 0 < L.

Uniformity keeps the theory simple, and for me this is a theory exercise.

Let's say

    ]M =: 1;2
┌─┬─┐
│1│2│
└─┴─┘

then

    (0$a:) -: M -. M
1

that is, M -. M appropriately matches your proposed empty set.  But

    L. M -. M
0

so the operation -. has led to a not boxed result, and of course your proposed 
empty set also is not boxed.  My use of a: provides the uniformity I wanted.

As a practical matter, once the few fundamental definitions are written, we can 
use them without thinking about a: or the fact E =: ,a:  -- and I think the 
display

    E
┌┐
││
└┘

is a bonus.  The joke about the Chesire-Cat helps with the reading.  Carroll 
was a mathematician, and I wonder whether he was thinking about the empty set!

Kip


On 10/10/2010 4:57 PM, Marshall Lochbaum wrote:
> But does it serve a purpose? When every single verb you have has to be 
> adjusted for the end of the set not being an element, it doesn't really make 
> much sense to keep a: .
>
> Marshall
>
> -----Original Message-----
> From: [email protected] 
> [mailto:[email protected]] On Behalf Of Kip Murray
> Sent: Sunday, October 10, 2010 5:15 PM
> To: Programming forum
> Subject: Re: [Jprogramming] Sets
>
> The Ace a: is like the grin on Lewis Carroll's Chesire-Cat.  When everything 
> disappears except the grin, you are looking at the empty set.
>
>
> On 10/10/2010 11:51 AM, Marshall Lochbaum wrote:
>> I don't see the usefulness of the a: at the end of the sets. An empty set 
>> should just be represented by 0$a:, and is clearly identifiable because it 
>> gives no output.
>>
>> Marshall
>>
>> -----Original Message-----
>> From: [email protected] 
>> [mailto:[email protected]] On Behalf Of Kip Murray
>> Sent: Sunday, October 10, 2010 12:02 AM
>> To: Programming forum
>> Subject: [Jprogramming] Sets
>>
>> Here is my latest attempt to model set theory in J.  All sets have 
>> distinct elements and are ordered by /:~ so that match -: determines 
>> whether two sets are the same.  Sets must be created by the verb set 
>> or by provided operations.  The intention is theoretical not 
>> practical!  --Kip Murray
>>
>>       ]A =: set 0;'b';2  NB. elements 0 'b' 2 are put in boxes preceding the 
>> last ┌─┬─┬─┬┐ │0│2│b││ └─┴─┴─┴┘
>>       ]B =: set 2;'b';'b';0  NB. same elements so same set ┌─┬─┬─┬┐ 
>> │0│2│b││ └─┴─┴─┴┘
>>
>>       A -: B
>> 1
>>
>>       ]C =: set 2;'b';'c';'d'
>> ┌─┬─┬─┬─┬┐
>> │2│b│c│d││
>> └─┴─┴─┴─┴┘
>>
>>       B sand C  NB. intersection, "set and"
>> ┌─┬─┬┐
>> │2│b││
>> └─┴─┴┘
>>       B sor C   NB. union
>> ┌─┬─┬─┬─┬─┬┐
>> │0│2│b│c│d││
>> └─┴─┴─┴─┴─┴┘
>>
>>       (A sand B sor C) -: (A sand B) sor (A sand C)  NB. distributive 
>> law
>> 1
>>
>>       pwrset A  NB. A has 3 elements, power set has 2^3, including 
>> the empty set ┌──────┬────────┬────┬──────┬────┬──────┬──┬────┬┐
>> │┌─┬─┬┐│┌─┬─┬─┬┐│┌─┬┐│┌─┬─┬┐│┌─┬┐│┌─┬─┬┐│┌┐│┌─┬┐││
>> ││0│2││││0│2│b││││0││││0│b││││2││││2│b│││││││b││││
>> │└─┴─┴┘│└─┴─┴─┴┘│└─┴┘│└─┴─┴┘│└─┴┘│└─┴─┴┘│└┘│└─┴┘││
>> └──────┴────────┴────┴──────┴────┴──────┴──┴────┴┘
>>       NB. Elements are contained in boxes preceding the last which is always
>>       NB. the Boxed Empty a: (Ace).  The use of a: permits a unique and 
>> visible
>>       NB. empty set, viz
>>
>>       (,a:) -: E =: A less A  NB. see verb less below
>> 1
>>       E
>> ┌┐
>> ││
>> └┘
>>       a:
>> ┌┐
>> ││
>> └┘
>>       E -: a:
>> 0
>>
>> NB. Definitions
>>
>> E =: ,a:                 NB. empty set
>> set =: a: ,~ [: /:~ ~.   NB. create set from boxed list y
>>                             NB. each box of y encloses an element
>> get =: { }:              NB. get boxed elements (from curtail because
>>                             NB. elements are inside boxes of curtail)
>> isin =: e. }:            NB. Do boxes in list x contain elements of y?
>> less =: a: ,~ -.&}:      NB. remove elements of y from x
>> sand =: [ less less      NB. intersection, "set and"
>> sor =: a: ,~ [: /:~ [: ~. ,&}:  NB. union, "set or"
>> diff =: less sor less~   NB. symmetric difference
>> card =: [: # }:          NB. count elements: cardinality
>> issubs =: [ -: sand      NB. Is x a subset of y?
>> pwrset =: a: ,~ [: /:~ ] (<@#~) 1 (,~"1) 2 (#"1~ {:)@#:@i...@^ #...@}:
>>                             NB. pwrset by Raul Miller, adapted
>> islist =: 1 = #...@$        NB. islist through isunique from validate.ijs
>> isboxed =: 0<   L.
>> issorted =: -: /:~
>> isunique =: -: ~.
>> isset =: islist *. isboxed *. (a: -: {:) *. issorted@:}: *. isunique@:}:
>>                             NB. isset y asks, is array y a set?
>> iselement =:<@[ isin ]  NB. Is array x an element of set y?
>>
>> NB. End
>>
>> ---------------------------------------------------------------------
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