Raul Miller-4 wrote:
> 
> On Fri, Nov 12, 2010 at 2:42 AM, Viktor Cerovski
> <[email protected]> wrote:
>> Raul Miller-4 wrote:
>>> On Thu, Nov 11, 2010 at 6:39 PM, Viktor Cerovski
>>> <[email protected]> wrote:
>>>> 1) absolute/explicit ranks are non-negative ones
>>>> 2) negative/relative ranks, and,
>>>> 3) infinite/undefined ranks.
>>>>
>>>> For the first kind equation v"v === v holds, but not for the other two
>>>> kinds.
>>>
>>> Where does case 3 differ?
>>>
>> For example, If we have two verbs v"_1 and v"_, the actual rank of the
>> former is derived from the shape of the argument(s) provided, while
>> the actual rank of  the latter is derived from the rank of v alone. Both
>> are of course different from, say, v"1, which has rank 1 1 1.
> 
> v"_1 is case 2, not case 3.
> 
Exactly, I was exemplifying the difference between these two cases.


> if v"_ is an example then +"1 would also be an example.
> 
It would in a trivial sense, since we know that the rank of + is 0 0 0.

In the case of v"_, however, there is no way to figure out action of the
verb without inspecting v.  Even then, v might have again rank _, and
then we still don't know the action of the verb until further inspection 
of its action.  Consider for instance cases when v is ]@:+ or +/ or 
(+ +/"1).  All three have infinite ranks according to b. 0 but all the 
same different cell actions, that could be described with ranks 
0, _ and 0 1, respectively.

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