On Sat, Apr 9, 2011 at 10:47 AM, Steven Taylor <[email protected]> wrote:
> f=:13 : '1 (x)}y$0'
>    3 5 7 f 10$0
> 0 0 0 1 0 1 0 1 0 0
...
> for f2... but wondered if there was a way to achieve this tacitly.  I'm

   f=:13 : '1 (x)}y$0'
   3 5 7 f 10$0
|index error: f
|   1    (x)}y$0
   F=:13 : '1 (x)}y'
   3 5 7 f 10$0
0 0 0 1 0 1 0 1 0 0

I am going to assume you were asking for a tacit replacement for F

   F3=:  1:`[`]}
   3 5 7 F3 10$0
0 0 0 1 0 1 0 1 0 0

FYI,

-- 
Raul
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