You can express this tacitly like this: f2=: 1:`[`]} 3 5 7 f2 10#0 0 0 0 1 0 1 0 1 0 0
From the dictionary page for m} http://www.jsoftware.com/help/dictionary/d530n.htm If m is a gerund, one of its elements determines the index argument to the adverb } , and the others modify the arguments x and y : x (v0`v1`v2)} y ↔ (x v0 y) (x v1 y)} (x v2 y) (v0`v1`v2)} y ↔ (v1 y)} (v2 y) (v1`v2)} y ↔ (v1 y)} (v2 y) On Sun, Apr 10, 2011 at 2:47 AM, Steven Taylor <[email protected]> wrote: > f=:13 : '1 (x)}y$0' > 3 5 7 f 10$0 > 0 0 0 1 0 1 0 1 0 0 > (correct) > > but > f2=:1([)}0$~] > 3 5 7 f2 10 > 0 1 0 0 0 0 0 0 0 0 > I can see that there are some challenges from the boxed notation returned > for f2... but wondered if there was a way to achieve this tacitly. I'm > guessing, but f looks like it is less efficient because it resolves to 4:1 > (x)}y$0. i.e. interpret a string on-the-fly. > > thanks, > -Steven > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm > ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
