You need to turn the result back into numbers after doing the "filled copy"
(1j1#):

   ".1j1#":12345
1 2 3 4 5
   +/".1j1#":12345
15

2011/4/29 Björn Helgason <[email protected]>

> 1j1#":12345
>
> 2011/4/29 bill lam <[email protected]>
>
> > one way is
> >   ]a=. ".,.":12345
> > 1 2 3 4 5
> >    +/a
> > 15
> >
> > project euler?
> >
> > Птн, 29 Апр 2011, Daniel Roe писал(а):
> > >
> > > If we add up the digits of the number 12345 we get 1+2+3+4+5 = 15.
> > > I want to be able to do math upon the individual digits.
> > > How would I do that in J?
> > > Dan
> > >
> > > ----------------------------------------------------------------------
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> >
> > --
> > regards,
> > ====================================================
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> > gpg --keyserver subkeys.pgp.net --recv-keys 4434BAB3
> > ----------------------------------------------------------------------
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> >
>
>
>
> --
> Björn Helgason, Verkfræðingur
> Fornustekkum II
> 781 Hornafirði,
> t-póst: [email protected]
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> twitter: @flugfiskur
> http://groups.google.com/group/J-Programming
>
>
> Tæknikunnátta höndlar hið flókna, sköpunargáfa er meistari einfaldleikans
>
> góður kennari getur stigið á tær án þess að glansinn fari af skónum
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-- 
Devon McCormick, CFA
^me^ at acm.
org is my
preferred e-mail
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