I anything to prefer if the digits are pure 0/1 ?
Working with QR codes you may get strings like
a=.'1111111011101100011100010000110100100100......
$a
4829
b=. 1j1 # a
$b
9658
b
1 1 1 1 1 1 1 0 1 1 1 0 1 1 0 0 0 1 1 1 0 0 0 1 0
c=. "."0 b
$c
9658 1
2011/4/29 Roger Hui <[email protected]>
> Aha! A dual:
>
> 1j1&#&.": 12345
> 1 2 3 4 5
>
> The fastest expression for obtaining the decimal digits is:
> http://www.jsoftware.com/help/release/digits10.htm
>
> 0"."0@": 12345
> 1 2 3 4 5
>
>
>
> ----- Original Message -----
> From: Devon McCormick <[email protected]>
> Date: Friday, April 29, 2011 5:48
> Subject: Re: [Jprogramming] sum of digits in a number
> To: Programming forum <[email protected]>
>
> > You need to turn the result back into numbers after doing the
> > "filled copy"
> > (1j1#):
> >
> > ".1j1#":12345
> > 1 2 3 4 5
> > +/".1j1#":12345
> > 15
> >
> > 2011/4/29 Björn Helgason <[email protected]>
> >
> > > 1j1#":12345
> > >
> > > 2011/4/29 bill lam <[email protected]>
> > >
> > > > one way is
> > > > ]a=. ".,.":12345
> > > > 1 2 3 4 5
> > > > +/a
> > > > 15
> > > >
> > > > project euler?
> > > >
> > > > Птн, 29 Апр 2011, Daniel Roe писал(а):
> > > > >
> > > > > If we add up the digits of the number 12345 we get
> > 1+2+3+4+5 = 15.
> > > > > I want to be able to do math upon the individual digits.
> > > > > How would I do that in J?
>
> ----------------------------------------------------------------------
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>
--
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