I have been working on my version of findinrows so that it will work
on repeated strings such as 'TAGG' but need some help in proceeding
further.
findinrows=: (0~:#)&>@{."1@([:(({.@:i.}.[);}.@])&>/"1^:_ (,&<)"1)
NB. this is the original
findinrows=: (0~:#)&>@{."1@([:((([{.@:(>:@i.){.@])}.[);}.@])&>/"1^:_
(,&<)"1) NB. this is a slight update where One is added to the result
of dyadic i.
But instead of _ for the count of repeat, the number letters in the y
argument needs to be used. So, for example with 'TAG' I need ^:3 and
for 'TAGG' I need ^:4 . The result is quite fast but I have not been
able to make the argument to ^: a variable amount.
On Thu, Aug 18, 2011 at 3:34 PM, Brian Schott <[email protected]> wrote:
> findinrows=: (0~:#)&>@{."1@([:(({.@:i.}.[);}.@])&>/"1^:_ (,&<)"1)
> A findinrows 'TAG'
>
--
(B=) <-----my sig
Brian Schott
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