Raul, Yes, I had tried something like that but got it wrong then. Now with you idea I think this is better, but a little ugly. Thnx, much.
findinrows=:
(0~:#)&>@{."1@([:((([{.@:(>:@i.){.@])}.[);}.@])&>/"1^:(#@(>@{:@:{.@]))
(,&<)"1)
On Sat, Aug 20, 2011 at 7:47 PM, Raul Miller <[email protected]> wrote:
> ^:(#@]) ?
>
> --
> Raul
>
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