2011/10/29 Henry Rich <[email protected]>:
> It is true, as I said, that /:~~ produces the same result as /:~ :/: but
> it might not perform the same.  The monad /:~ is backed by special code,
> but when you execute /:~~ you are not executing that monad.  Unless
> Roger was being unusually thorough, /:~~ would go through dyad /: which
> is a different algorithm.  You'd have to check timings to see.
>
> Since what you are executing here is always a monad, /:~ is preferable.

The parser sees /:~~ as (/:~)~

So it's hard to imagine how it could miss the special code for /:~

-- 
Raul
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