Just a quibble with terminology: 'item' means _1-cell. That concept does not apply here. If you define 'l-cell' to be the left rank of the verb, and 'r-cell' the right rank, you could say
...it loops through all the l-cells of x, then for each of those, all the r-cells of y... Henry Rich On 11/4/2011 12:13 AM, Marshall Lochbaum wrote: > * has rank 0 already, so it isn't necessary. The definition of / is that it > applies the verb with rank (left rank),_ . Essentially, this means that it > loops through all the items of x, then for each of those, all the items of > y, where an "item" is an item with the left rank of the verb. If you try > magic/~ a with magic having rank _ (because it's a fork), you just get (a > magic"_ _"_ _ a), which simply applies magic regularly. > > Marshall > > On Thu, Nov 3, 2011 at 11:57 PM, Ricardo Forno<[email protected]>wrote: > >> I have this verb: >> magic =: * %>:@(+:@*) - + >> that I use only as a dyad, and, say, >> a =: 0.1 * i. 10 >> If I want to get a table of the * verb, I write: >> a * / a >> If I write >> a magic / a >> I dont get a table. To get a table, I have to write: >> a magic"0 / a >> Why is it so, since both * and magic may be used as dyads? >> Thanks. >> >> >> ---------------------------------------------------------------------- >> For information about J forums see http://www.jsoftware.com/forums.htm >> > ---------------------------------------------------------------------- > For information about J forums see http://www.jsoftware.com/forums.htm > ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
