I believe it is correct that a fork has rank _ . You can experiment
using b. as shown below:
(+ * -) b. 0
_ _ _
+ b. 0
0 0 0
* b. 0
0 0 0
- b. 0
0 0 0
(The ranks of the verb on the left are given in the order monadic left
right.)
On 11/4/2011 5:30 AM, Ricardo Forno wrote:
> The thing that confused me is that I didn't know a fork has rank _ as
> Marshall wrote. Is that correct? Browsing through Learning J, I couldn't
> find if this fact is mentioned there.
>
> ----- Original Message -----
> From: "Henry Rich"<[email protected]>
> To: "Programming forum"<[email protected]>
> Sent: Friday, November 04, 2011 7:15 AM
> Subject: Re: [Jprogramming] Newbie question
>
>
>> Just a quibble with terminology: 'item' means _1-cell. That concept
>> does not apply here. If you define 'l-cell' to be the left rank of the
>> verb, and 'r-cell' the right rank, you could say
>>
>> ...it loops through all the l-cells of x, then for each of those, all
>> the r-cells of y...
>>
>> Henry Rich
>>
>> On 11/4/2011 12:13 AM, Marshall Lochbaum wrote:
>>> * has rank 0 already, so it isn't necessary. The definition of / is that
>>> it
>>> applies the verb with rank (left rank),_ . Essentially, this means that
>>> it
>>> loops through all the items of x, then for each of those, all the items
>>> of
>>> y, where an "item" is an item with the left rank of the verb. If you try
>>> magic/~ a with magic having rank _ (because it's a fork), you just get (a
>>> magic"_ _"_ _ a), which simply applies magic regularly.
>>>
>>> Marshall
>>>
>>> On Thu, Nov 3, 2011 at 11:57 PM, Ricardo
>>> Forno<[email protected]>wrote:
>>>
>>>> I have this verb:
>>>> magic =: * %>:@(+:@*) - +
>>>> that I use only as a dyad, and, say,
>>>> a =: 0.1 * i. 10
>>>> If I want to get a table of the * verb, I write:
>>>> a * / a
>>>> If I write
>>>> a magic / a
>>>> I dont get a table. To get a table, I have to write:
>>>> a magic"0 / a
>>>> Why is it so, since both * and magic may be used as dyads?
>>>> Thanks.
>>>>
>>>>
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>>>>
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>
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