Here is the challenge. Use the arguments a and b and define a single tacit
function in "simple J" that does not use @ and provides the same result. (Use
forks, hooks and rank) Then the result of:
a table b
should match the result in the Dictionary or the result attached to this
message.
-----Original Message-----
From: [email protected]
[mailto:[email protected]] On Behalf Of Raul Miller
Sent: Monday, November 14, 2011 9:20 AM
To: Programming forum
Subject: Re: [Jprogramming] table challenge in simple J
Which conditions are not satisfied?
--
Raul
On Mon, Nov 14, 2011 at 8:52 AM, Linda Alvord <[email protected]> wrote:
> This does not satisfy the conditions of the problem. Also, wait until
> November 18th for more hints. Thanks.
>
> Linda
>
>
> -----Original Message-----
> From: [email protected]
> [mailto:[email protected]] On Behalf Of Raul Miller
> Sent: Monday, November 14, 2011 7:41 AM
> To: Programming forum
> Subject: Re: [Jprogramming] table challenge in simple J
>
> over=:[: ({.;}.) [: ": ,
> by=: (' ' ; [: ,. [),.]
>
> --
> Raul
>
> 2011/11/13 Linda Alvord <[email protected]>:
>> In the dictionary in the section on "Verbs and Adverbs" there are two
>> definitions designed to produce a table:
>>
>>
>>
>> over=:({.;}.)@":@,
>>
>> by=:' '&;@,.@[,.]
>>
>> a=: 2 3 5
>>
>> b=: 0 1 2 3
>>
>> a by b over a +/ b
>>
>> --T-------┐
>>
>> │ │0 1 2 3│
>>
>> +-+-------+
>>
>> │2│2 3 4 5│
>>
>> │3│3 4 5 6│
>>
>> │5│5 6 7 8│
>>
>> L-+--------
>>
>>
>>
>> Here is the challenge. Use the arguments a and b and define a single tacit
>> function in "simple J" that does not use @ and provides the same result.
>>
>>
>>
>> a table b
>>
>> --T-------┐
>> │ │0 1 2 3│
>> +-+-------+
>> │2│2 3 4 5│
>> │3│3 4 5 6│
>> │4│4 5 6 7│
>> L-+--------
>>
>>
>>
>> To give a little time for thought, do not post a solution until November
>> 18th. I'll post mine then too.
>>
>>
>>
>> Linda
>>
>> ----------------------------------------------------------------------
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>
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