It's rather difficult to participate in a discussion where I am not
supposed to respond.  (It was also not clear in the original message
that responses were to be embargo'd).

But I will try to ignore this thread until Friday.

-- 
Raul

On Mon, Nov 14, 2011 at 12:25 PM, Linda Alvord <[email protected]> wrote:
> Please do not respond until November 18th.  Both  by  and  over contain  @  
> so you need to define a single tacit function that does not include it.
>
> -----Original Message-----
> From: [email protected] 
> [mailto:[email protected]] On Behalf Of Raul Miller
> Sent: Monday, November 14, 2011 9:34 AM
> To: Programming forum
> Subject: Re: [Jprogramming] table challenge in simple J
>
> Oh, nvm, I see:
>
>  a (by over +/) f. b
>
> --
> Raul
>
> On Mon, Nov 14, 2011 at 9:19 AM, Raul Miller <[email protected]> wrote:
>> Which conditions are not satisfied?
>>
>> --
>> Raul
>>
>> On Mon, Nov 14, 2011 at 8:52 AM, Linda Alvord <[email protected]> 
>> wrote:
>>> This does not satisfy the  conditions of the problem.  Also, wait until 
>>> November 18th for more hints.  Thanks.
>>>
>>> Linda
>>>
>>>
>>> -----Original Message-----
>>> From: [email protected] 
>>> [mailto:[email protected]] On Behalf Of Raul Miller
>>> Sent: Monday, November 14, 2011 7:41 AM
>>> To: Programming forum
>>> Subject: Re: [Jprogramming] table challenge in simple J
>>>
>>>   over=:[: ({.;}.) [: ": ,
>>>   by=: (' ' ; [: ,. [),.]
>>>
>>> --
>>> Raul
>>>
>>> 2011/11/13 Linda Alvord <[email protected]>:
>>>> In the dictionary in the section on "Verbs and Adverbs" there are two
>>>> definitions designed to produce a table:
>>>>
>>>>
>>>>
>>>>       over=:({.;}.)@":@,
>>>>
>>>>       by=:' '&;@,.@[,.]
>>>>
>>>>      a=: 2 3 5
>>>>
>>>>      b=: 0 1 2 3
>>>>
>>>>    a by b over a +/ b
>>>>
>>>> --T-------┐
>>>>
>>>> │ │0 1 2 3│
>>>>
>>>> +-+-------+
>>>>
>>>> │2│2 3 4 5│
>>>>
>>>> │3│3 4 5 6│
>>>>
>>>> │5│5 6 7 8│
>>>>
>>>> L-+--------
>>>>
>>>>
>>>>
>>>> Here is the challenge.  Use the arguments a and b and define a single tacit
>>>> function in "simple J" that does not use  @  and provides the same result.
>>>>
>>>>
>>>>
>>>>    a table b
>>>>
>>>> --T-------┐
>>>> │ │0 1 2 3│
>>>> +-+-------+
>>>> │2│2 3 4 5│
>>>> │3│3 4 5 6│
>>>> │4│4 5 6 7│
>>>> L-+--------
>>>>
>>>>
>>>>
>>>> To give a little time for thought, do not post a solution until November
>>>> 18th. I'll post mine then too.
>>>>
>>>>
>>>>
>>>> Linda
>>>>
>>>> ----------------------------------------------------------------------
>>>> For information about J forums see http://www.jsoftware.com/forums.htm
>>> ----------------------------------------------------------------------
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>>>
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>>> For information about J forums see http://www.jsoftware.com/forums.htm
>>
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> For information about J forums see http://www.jsoftware.com/forums.htm
>
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