Great! This works too. f=: 13 :'*:@+/y' g=: 13 :'([:*:+)/y' f *:@+/
g ([: *: +)/ Thanks Linda -----Original Message----- From: programming-boun...@jsoftware.com [mailto:programming-boun...@jsoftware.com] On Behalf Of R.E. Boss Sent: Sunday, February 05, 2012 7:53 AM To: 'Programming forum' Subject: Re: [Jprogramming] Another early morning exercise > -----Oorspronkelijk bericht----- > Van: programming-boun...@jsoftware.com [mailto:programming- > boun...@jsoftware.com] Namens Linda Alvord > Verzonden: zondag 5 februari 2012 13:12 > Aan: 'Programming forum' > Onderwerp: [Jprogramming] Another early morning exercise > > My goal has been to translate from expressions with @ to ones without it. > (...) > > > Can you rewrite this without @ ? > > > > i=: 13 :'*:@+/x' > > i i.4 > > 456976 > ([: *: +)/i.4 456976 R.E. Boss ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm
