I meant (to the left of) in the post below this one.

Is  g  a request for a dyadic function or a monadic one?  Since the results
are different, why does  g  have the right  [:  before (to the right of) two
"verbs" if  [  represents a noun ?

Linda

-----Original Message-----
From: programming-boun...@jsoftware.com
[mailto:programming-boun...@jsoftware.com] On Behalf Of Linda Alvord
Sent: Sunday, February 05, 2012 10:33 PM
To: 'Programming forum'
Subject: Re: [Jprogramming] Another early morning exercise

Dave Lambert mentioned to me in a post that I had made a typing error typing
x  instead of y :

   i=: 13 :'*:@+/x'
   i i.4
456976

So, here are two questions:

   f=: 13 :'%#y'
   f
[: % #
   g=: 13 :'%#x'
   g
[: % [: # [

Is  g  a request for a dyadic function or a monadic one?  Since the results
are different, why does  g  have the right  [:  before (to the right of) two
"verbs" if  [  represents a noun ?

I've often seen this before and wondered about it.

Linda
-----Original Message-----
From: programming-boun...@jsoftware.com
[mailto:programming-boun...@jsoftware.com] On Behalf Of Don Guinn
Sent: Sunday, February 05, 2012 8:21 AM
To: Programming forum
Subject: Re: [Jprogramming] Another early morning exercise

Don't you need to change the x to y?

  i=: 13 :'*:@+/y'
  i i.4
456976
  i=: 3 :'*:@+/y'
  i i.4
456976
  i=: 3 :'*:@+/x'
  i i.4
676

On Sun, Feb 5, 2012 at 5:11 AM, Linda Alvord <lindaalv...@verizon.net>wrote:

> My goal has been to translate from expressions with  @  to ones without
it.
>
>
>
>   f=: 13 :'x?@$y'
>
>   2 3 f 6
>
> 2 4 2
> 3 2 5
>
>
>
>   g=: 13 :'x?$y'
>
>   2 3 g 6
>
> |length error: g
> |   2 3     g 6
>
>
>
>   h=: 13 :'?x$y'
>
>   2 3 h 6
>
> 4 3 1
> 5 0 1
>
>
>
>   f
>
> ?@$
>
>   h
>
> [: ? $
>
>
>
> Can you rewrite this without @ ?
>
>
>
>   i=: 13 :'*:@+/x'
>
>   i i.4
>
> 456976
>
>
>
>
>
> Linda
>
> ----------------------------------------------------------------------
> For information about J forums see http://www.jsoftware.com/forums.htm
>
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