Hi all,
I have the following data
bgpPeerAdminStatus{bgpPeerAdminStatus="start",bgpPeerRemoteAddr="10.0.0.66",
bgpPeerRemoteAs="1",instance="10.0.0.1",job="snmp-cisco-bgp"} 1
bgpPeerState{bgpPeerRemoteAddr="10.0.0.66",bgpPeerRemoteAs="1",bgpPeerState=
"idle",instance="10.0.0.1",job="snmp-cisco-bgp"} 1
and the alert
- alert: BGPPeer
expr: bgpPeerAdminStatus{bgpPeerAdminStatus="start"} == 1 and on(
instance, bgpPeerRemoteAddr) bgpPeerState{bgpPeerState!="established"} == 1
for: 1m
labels:
team: noc
annotations:
summary: "BGP Peer {{ $labels.bgpPeerRemoteAs }} state is {{
$labels.bgpPeerState }}"
description: "BGP Peer {{ $labels.bgpPeerRemoteAs }} (remote address:
{{ $labels.bgpPeerRemoteAddr }}) has state {{ $labels.bgpPeerState }}"
The alert is working, but it doesn't return the bgpPeerState from the RHS
of the expression. Writing this I just realised I can reverse the
expression and get the peer state, but I guess my question still remains -
how can I combine conditions but keep all the labels from both sides even
when they don't match? group_left doesn't work with the boolean operators -
'no grouping allowed for "and" operation'
Thanks!
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