Hi all,
I guess this isn't possible in PromQL
Is there another way to check two conditions for a single alert?
Boden
On Friday, 29 May 2020 09:09:24 UTC+10, Boden Garman wrote:
>
> Hi all,
>
> I have the following data
> bgpPeerAdminStatus{bgpPeerAdminStatus="start",bgpPeerRemoteAddr=
> "10.0.0.66",bgpPeerRemoteAs="1",instance="10.0.0.1",job="snmp-cisco-bgp"}
> 1
> bgpPeerState{bgpPeerRemoteAddr="10.0.0.66",bgpPeerRemoteAs="1",
> bgpPeerState="idle",instance="10.0.0.1",job="snmp-cisco-bgp"} 1
>
>
> and the alert
> - alert: BGPPeer
> expr: bgpPeerAdminStatus{bgpPeerAdminStatus="start"} == 1 and on(
> instance, bgpPeerRemoteAddr) bgpPeerState{bgpPeerState!="established"} ==
> 1
> for: 1m
> labels:
> team: noc
> annotations:
> summary: "BGP Peer {{ $labels.bgpPeerRemoteAs }} state is {{
> $labels.bgpPeerState }}"
> description: "BGP Peer {{ $labels.bgpPeerRemoteAs }} (remote
> address: {{ $labels.bgpPeerRemoteAddr }}) has state {{ $labels.bgpPeerState
> }}"
>
> The alert is working, but it doesn't return the bgpPeerState from the RHS
> of the expression. Writing this I just realised I can reverse the
> expression and get the peer state, but I guess my question still remains -
> how can I combine conditions but keep all the labels from both sides even
> when they don't match? group_left doesn't work with the boolean operators -
> 'no grouping allowed for "and" operation'
>
> Thanks!
>
>
>
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