Strange, I don't know why you'd be getting permission denied errors, but I'm
glad you figured out something that works.
On Fri, Oct 10, 2008 at 7:38 AM, <[EMAIL PROTECTED]> wrote:
> I also noticed that I get a permission denied error if I specify
> either a valid path or "." for the --proto_path argument on the
> command line. What I did to get it to work was to cd to the directory
> the file is in, and then simply pass the file name to --cpp_out
> without passing a --proto_path argument. The resulting code is now
> compiles :)
> Below is how got .proto files compiling with protoc as a custom build
> step in VS:
> protobuild.cmd [inputs]
> protobuild.cmd is the following:
> @echo off
> cd "%~p1"
> protoc.exe --cpp_out= "%~n1%~x1"
> The reason for the .cmd file is that the [inputs] macro from VS
> provides the .proto file to the command line using a relative path.
> The cmd file takes the relative path and expands it out to a fully
> qualified path, filename and extension and passes it to protoc.
> On Oct 9, 5:00 pm, "Kenton Varda" <[EMAIL PROTECTED]> wrote:
> > On Thu, Oct 9, 2008 at 12:52 PM, <[EMAIL PROTECTED]> wrote:
> > > protoc.exe --cpp_out= "[Fully qualified path name]"
> > Ah, ok, you've identified a bug. protoc is supposed to reject any input
> > file which is not located within the import path. The import path is
> > specified using --proto_path and defaults to the current directory. The
> > problem is that protoc detects whether an input file's path is absolute
> > based on whether it starts with a slash, but on Windows absolute paths
> > start with a slash. So, protoc failed to report the incorrect input
> > To fix this, you can either do:
> > protoc --proto_path="[full path of current directory]" --cpp_out=.
> > path of input file]"
> > Or do:
> > protoc --cpp_out=. "[file name without path]"
> > I'll make sure the bug gets fixed. Thanks.
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