I have some file. Let's call it *Msg.proto* I use Google's protoc.exe compiler to take my proto file and it generates a *Msg.h* file, which contains the definition for a *Msg* class. When I *delete* a *Msg* object it can take a really long to deallocate the memory (when the debugger is attached). This is because it is using the STL debug library. So, I want to disable STL debugging when I *delete* *Msg* objects, but I want to keep STL debugging *for the rest of my project*. This leads me to consider compiling the protocol buffers project without STL debugging info.
What are the implications of this? This means that all *Msg* objects will not have STL debugging info, right? Consequently, no STL objects created with STL debugging info can be passed into any of *Msg's* functions/constructors/etc, right? -- You received this message because you are subscribed to the Google Groups "Protocol Buffers" group. To view this discussion on the web visit https://groups.google.com/d/msg/protobuf/-/JSw1kIA_FywJ. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/protobuf?hl=en.
