It's just the standard IEEE 64-bit double encoding...
>>> struct.pack('d', 1.0)
'\x00\x00\x00\x00\x00\x00\xf0?'
[and of course ? == 0x3F]
On Mon, Sep 2, 2013 at 11:23 AM, Sébastien Muscat <[email protected]> wrote:
> Hi,
>
> I'm new with protocol buiffer and I try to understand the double encoding.
>
> I try to encode 1 and the result value is :
>
> 09 00 00 00 00 00 00 F0 3F
>
> I understand that 09 is tag and wire type and the next 8 bytes are the value
> 1 encoded.
>
> But how 1 is encoded into F0 3F ?
>
> thanks for your answers
>
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