Or, if there's a situation where any() or all() doesn't suit, you can
break each() loops by throwing $break.
--
T.J. Crowder
tj / crowder software / com
On Oct 9, 10:04 am, Tomasz Kalkosiński <[EMAIL PROTECTED]>
wrote:
> Nah! I've just discovered Enumerable.any() and Enumerable.all(). That
> should do the trick.
>
> Sorry for hassle <o>
>
> Greetings,
> Tomasz Kalkosiński
>
> On Oct 9, 10:47 am, Tomasz Kalkosiński <[EMAIL PROTECTED]>
> wrote:
>
> > I'm refactoring old code and I use Enumerable.each() wherever
> > possible. I've came to problem like this:
>
> > function checkSomething (arr)
> > for (i=0 ; i < arr.length ; i++) {
> > var c = arr[i];
> > if (c == 15) return true;
> > }
> > return false;
>
> > }
>
> > My question is can I do "short-circuit" return from inside
> > each( function (c) {...} ) ? When I do return it's just like old throw
> > $continue and it's not what I mean.
>
> > Greetings,
> > Tomasz Kalkosiński
>
>
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