Thank u for reply, But I did not use "this" word in my code!!!

On May 14, 3:13 pm, Marslander <yazev...@gmail.com> wrote:
> That is because you call Prototype method 'this.clonePosition' by
> clicking your button. In this case 'this' - is the button itself
> (extended element). You need to rename your 'clonePosition' function.
>
> On May 13, 2:54 pm, Alaa <ala...@gmail.com> wrote:
>
> > Hello,
> > From it is name I expect that the two elements will have the same
> > position after cloning the position, but nothing happens!!!
>
> > here is the example
> > <html>
> > <head>
> > <title>Prototype examples</title>
> > <script type="text/javascript"
> >    src="/javascript/prototype.js">
> > </script>
> > <script>
>
> > function clonePosition(){
> >    var firstElement = $('firstDiv');
> >    var secondElement = $('secondDiv');
> >    secondElement.clonePosition( firstElement);
>
> > }
>
> > </script>
> > </head>
>
> > <body>
>
> >    <p>Click Clone Position button to see the result.</p>
> >    <div id="firstDiv">
> >       <p>This is first paragraph</p>
> >    </div>
>
> >    <div id="secondDiv">
> >       <p>This is second paragraph</p>
> >    </div>
>
> >    <br />
> >    <input type="button" value="Clone Position"
> >              onclick="clonePosition();"/>
>
> > </body>
> > </html>
>
> > So, is that a bug, or I have some mistakes, or it is not doing as I
> > have understood???
>
> > help please
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