Hello,
>From it is name I expect that the two elements will have the same
position after cloning the position, but nothing happens!!!
here is the example
<html>
<head>
<title>Prototype examples</title>
<script type="text/javascript"
src="/javascript/prototype.js">
</script>
<script>
function clonePosition(){
var firstElement = $('firstDiv');
var secondElement = $('secondDiv');
secondElement.clonePosition( firstElement);
}
</script>
</head>
<body>
<p>Click Clone Position button to see the result.</p>
<div id="firstDiv">
<p>This is first paragraph</p>
</div>
<div id="secondDiv">
<p>This is second paragraph</p>
</div>
<br />
<input type="button" value="Clone Position"
onclick="clonePosition();"/>
</body>
</html>
So, is that a bug, or I have some mistakes, or it is not doing as I
have understood???
help please
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"Prototype & script.aculo.us" group.
To post to this group, send email to [email protected]
To unsubscribe from this group, send email to
[email protected]
For more options, visit this group at
http://groups.google.com/group/prototype-scriptaculous?hl=en
-~----------~----~----~----~------~----~------~--~---
