Is it returning an array ?
Check with
$$('div.fp_YouTube').each(function(el) {
var player = el.select('.player');
var playlist = el.select('.playlist');
alert(playlist); // see if its an object
return;
playlist.select('li').each(function(video) {
console.log(video.id);
});
});
if it is returning an array then try
$$('div.fp_YouTube').each(function(el) {
var player = el.select('.player');
var playlist = el.select('.playlist');
$(playlist).select('li').each(function(video) {
console.log(video.id);
});
});
HTH
Alex
----- Original Message -----
From: "Ian R" <[email protected]>
To: "Prototype & script.aculo.us" <[email protected]>
Sent: Wednesday, July 01, 2009 6:22 PM
Subject: [Proto-Scripty] "iterator.call is not a function"
>
>
> Ok. So I have a structure like this:
>
> <div class="fp_YouTube">
>
> <div class="player">
> <object width="425" height="349"> ... </object>
> </div>
>
> <ol class="playlist">
> <li id="YouTubeID_w7naKj-z5So"> ... </li>
> <li id="YouTubeID_naiN5V4Q1rI"> ... </li>
> </ol>
>
> </div>
>
> And eventually what I am doing is replacing the contents of "player"
> with a new video, based on observing a click on one of the list items
> in "playlist". I've done it before but I'm trying to prototypejs it
> up a little nicer.
>
> SO... I have this JS code going:
>
> $$('div.fp_YouTube').each(function(el) {
> var player = el.select('.player');
> var playlist = el.select('.playlist');
> playlist.select('li').each(function(video) {
> console.log(video.id);
> });
> });
>
>
> But firebug is telling me this:
>
> "iterator.call is not a function -- prototype.js (line 661)"
>
> I've noticed that if I console.log the original "el" variable, it
> looks like <div class="fp_YouTube"> but if I log the "playlist"
> variable, it comes out as [ol.playlist] ... is it returning a 1-item
> array? Is there something I am fundamentally misunderstanding,
> something I need to do in order to work with "playlist" the way I've
> been working with "el"?
>
> Thanks in advance, and pardon this message for misfiring and sending
> before I was ready.
>
> Ian
>
> >
>
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