It solved my problem, again. Thanks! On 14 oct, 09:20, Julius Seporaitis <jul...@seporaitis.net> wrote: > Garfieldius, thanks :) > > svens0n82, I've later found that function 'descendant' also needs similar > fix. Around line 3597 in prototype.js I've changed: > > h.concat(results, node.getElementsByTagName('*')); > > into > > if(typeof node == 'string') { node = $(node); } > h.concat(results, node.getElementsByTagName('*')); > > On Wed, Oct 14, 2009 at 10:59 AM, svens0...@googlemail.com < > > svens0...@googlemail.com> wrote: > > > Hi, > > > i have the same issue with the error but your solution doesnt work for > > me. Error keeps the same. > > > Any more ideas? > > > On 12 Okt., 23:16, Julius Šėporaitis <jul...@seporaitis.net> wrote: > > > Hi, > > > > just wanted to post a quick note for those who maybe had problems like > > > mine: > > > > - Prototype v.1.6.1 > > > - Firefox 3.5 > > > - JS Error: root.querySelectorAll is not a function (about line 3299 > > > in prototype.js) > > > > This started to happen on Magento checkout pages, where the Accordion > > > is and I don't know if this is a prototype bug or not, so - I don't > > > know why and when this happens, but on my situation initially - the > > > root variable is a string so it passes the initial check (root = root > > > || document) causing problems later. :) Here's a solution. > > > > in the prototype.js prepend this line (~3299): > > > > results = $A(root.querySelectorAll(e)).map(Element.extend); > > > > so it looks like this: > > > > if(typeof root == string) root = $(root); > > > results = $A(root.querySelectorAll(e)).map(Element.extend); > > > > I hope this gets helpful to someone. > > > > Cheers, > > > Julius Seporaitis > > -- > Cheers, > Julius Šėporaitis
--~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Prototype & script.aculo.us" group. To post to this group, send email to prototype-scriptaculous@googlegroups.com To unsubscribe from this group, send email to prototype-scriptaculous+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/prototype-scriptaculous?hl=en -~----------~----~----~----~------~----~------~--~---