The function you pass to each has a second optional index param: $$('.foo').each(function(elem, index) { elem.update('I am element ' + index); });
It's not all that clear in the docs but it's mentioned for the iterator param here: http://api.prototypejs.org/language/Enumerable/prototype/each/ Is that wat you were looking for? -- Marc On Feb 1, 12:12 am, Walter Lee Davis <wa...@wdstudio.com> wrote: > I have an extended array, result of $$('.foo'). Given a single member > of that array as an object, how do I find the next element in that > array, or the first if the next would wrap? > > I could swear there used to be an operator that worked over an > enumerable and maintained an index element as you went, so you could > reference by position within the enumerable, but I can't find it by > hunting in the documentation. Can anyone help me out? > > Thanks, > > Walter -- You received this message because you are subscribed to the Google Groups "Prototype & script.aculo.us" group. To post to this group, send email to prototype-scriptaculous@googlegroups.com. To unsubscribe from this group, send email to prototype-scriptaculous+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/prototype-scriptaculous?hl=en.