One way to do this is to add an overlay to your page.
<div id="overlay"></div>
#overlay {
position: static;
top: 0;
right: 0;
bottom: 0;
left: 0;
background: url(spinner.gif) rgba(0,0,0,0.7);
z-index: 1000;
}
document.observe('dom:loaded',function(){ $('overlay).hide();});
Then slave the show/hide to your Ajax methods, or use the technique outlined in
the AjaxResponders docs to have one listener for all Ajax events:
http://api.prototypejs.org/ajax/Ajax/Responders/
Walter
On May 8, 2012, at 10:54 AM, Phil Petree wrote:
> Lets say I have this div imbedded in my page:
> <div id='systemWorking'><img src='spinner.gif'>Saving...</div>
>
> And I have a list with 1000 entries and the user has scrolled down mid way...
> if I unhide the spinner using this:
> document.getElementById('inProgress').style.display = 'inline';
>
> It shows but it shows in the location where it's imbedded in the page (top,
> bottom etc.) but not necessarily viewable to the user. I want to reposition
> the div so that its always centered in the screen.
>
> How does one go about this?
>
> Thanks,
>
> Pete
>
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