Wow. I wonder why it just this minute came up for moderation? That's Google
Groups for you...
Walter
On Jul 17, 2013, at 4:12 PM, Jansen Nunes wrote:
> Hi
>
> My post is older(2010) and my project is finished now.
> Tks for all.
>
> Regards
>
>
> 2013/7/17 Walter Lee Davis <wa...@wdstudio.com>:
>> I
>> On Jul 17, 2013, at 3:37 PM, Joseph Lust wrote:
>>
>>> Ran into this issue on Prototype 1.5.1 and IE8.
>>
>> Is there a specific reason you are using such an old (years!) version of
>> Prototype? 1.7.1 is current, and even it is getting a little long in the
>> tooth.
>>
>>>
>>> The error is in the array without() function in IE8. without() should
>>> return an empty array if the array sans element is empty, or the array with
>>> that element removed.
>>>
>>> In IE8, if there are no elements left in the array after the target element
>>> is removed, undefined is returned, breaking anything chained after that.
>>>
>>> remove: function(classNameToRemove) {
>>> if (!this.include(classNameToRemove)) return;
>>> this.set($A(this).without(classNameToRemove).join(' '));
>>> },
>>
>> Are you trying to get an array of classnames from an element, or are you
>> trying to remove a class from an element? Because there's the
>> Element#removeClassName if the latter. It does pretty much what you do here,
>> except it returns an extended element, not an array of strings. You could
>> get the former with this:
>>
>>
>> $(this).removeClassName(classNameToRemove).className.toString().split(/\s+/);
>>
>> Walter
>>
>>>
>>> The actual source was that without() internally uses each() to iterate
>>> across the elements, but the DOMAssistant library have overwritten
>>> Element.each(). The new version could not catch the breaks that are thrown
>>> by Prototype to escape from deep nested iterators, and hence the error.
>>> Thus, the two libs should not be used in conjunction. It seems that other
>>> browsers don't overwrite the Element.each() method when loading the two
>>> libs like IE does.
>>>
>>>
>>>
>>> Sincerely,
>>> Joseph
>>>
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>>
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>
>
>
> --
> Jansen
>
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