On 2012-04-16 15:26, Antidot SAS wrote:
> A quick question for you, here is the code:
> $tt=regsubst("test","^(.*)->(.*)",'\2')
>
> Doesn't return: undef or nil, it does return: "test"
As expected and intended.
> Niether does $tt=regsubst("test","^(.?)->(.*)",'\2')
> or $tt=regsubst("test","^(.+?)->(.*)",'\2').
>
> Is there a way to return undef if the string doesn't include '->something' ?
Perhaps something like this:
$x = 'test'
$temp = regsubst($x, '^(.*)->(.*)', '\2')
if $temp == $x {
# No substitution done, must mean there is no "->" in $x
$tt = undef
} else {
$tt = $temp
}
Or perhaps this:
$tt = regsubst($x, '^(.*)->(.*)|.*', '\2')
It will however give you the empty string (""), not undef, if there is
no "->" in the string.
/Bellman
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