Ok, I totally forget that replacement part is not a search :D
On Mon, Apr 16, 2012 at 5:00 PM, Thomas Bellman <[email protected]> wrote: > On 2012-04-16 15:57, Antidot SAS top-posted: > > > Thx for the reply it helps. > > > > But how come the \2 returns something that I never asked? > > It doesn't. But since there are no occurrances of '^(.*)->(.*)', > then there are none that get replaced. Similarly, if you do: > > regsubst('foobar', 'x', 'y') > > you will get 'foobar', since there *is* no 'x' in 'foobar' that > can be replaced by a 'y'. > > > /Bellman > > -- > You received this message because you are subscribed to the Google Groups > "Puppet Users" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]. > For more options, visit this group at > http://groups.google.com/group/puppet-users?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Puppet Users" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/puppet-users?hl=en.
