so when you do this:
@foo
def bar(): pass
you assume that a function foo() already exists.
and it creates something like this:
def foo():
def bar(): pass
pass
?
I'm sorry, I just got confused.
- On Wed, 12/31/08, Noah Kantrowitz <n...@coderanger.net> wrote:
From: Noah Kantrowitz <n...@coderanger.net>
Subject: Re: [pygame] @
To: pygame-users@seul.org
Date: Wednesday, December 31, 2008, 3:01 AM
decorator. The short version is that this
@foo
def bar(): pass
is the same as this
def bar(): pass
bar = foo(bar)
The long version is "look it up because it gets very complicated and
voodoo-ish"
--Noah
On Dec 30, 2008, at 9:55 PM, Yanom Mobis wrote:
> I was reading some Python code examples, and i found the @ symbol. What
exactly does this operator do?
>
