Thanks, I see. I believe this way I do not need the .ini part, do I? On Thursday, March 17, 2016 at 3:40:28 AM UTC+1, Jonathan Vanasco wrote: > > > > On Wednesday, March 16, 2016 at 9:36:44 PM UTC-4, Zsolt Ero wrote: >> >> David Cramer from Sentry replied to me that if Sentry is used with the >> middleware, then it should automatically receive the WSGI context: >> from sentry.middleware import Sentry >> >> application = Sentry(application, client=Client(dsn, ...)) >> >> My problem is that in Pyramid I have no idea where could I get an >> application, or if this would work at all. >> > > That looks like the initial app setup in your `project/__init__.py` > > `application` would be what is returned from config.make_wsgi_app() > > Some people do "return config.make_wsgi_app()" > > Others prefer "app = config.make_wsgi_app()", then wrap it in middleware > > >
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