Yes, that is how I started. The problem is with client.captureException().
The problem is that there is no way to get the Client when it's
configured via ini (or at least I have no idea how to get it).
So when configured via ini, Sentry can only provide HTTP context for
uncaught exceptions which results in an Internal Server Error.
Obviously, your web app shouldn't result in Internal Server Errors,
but would try to give a reasonable error message, and internally log
the problem, so critical parts are in try-except blocks, and this is
where client.captureException() is used.
try:
...
except Exception:
client.captureException()
Now this client needs to be configured via a Sentry __call__, or else,
the http context is missing. That's why I needed to use the python
config vay.
On 20 March 2016 at 01:00, Michael Merickel <mmeri...@gmail.com> wrote:
> I'm missing something here probably but the raven docs have pretty
> straightforward support for configuring it via the ini file. Have you tried
> this?
>
> https://docs.getsentry.com/hosted/clients/python/integrations/pyramid/#pastedeploy-filter
>
> On Sat, Mar 19, 2016 at 5:44 PM, Zsolt Ero <zsolt....@gmail.com> wrote:
>>
>> Thanks, I was able to make a working client, but not using the pipeline +
>> filter part in the ini, but by wrapping app by:
>>
>> from raven import Client
>>
>> from raven.middleware import Sentry
>>
>>
>> client = Client('https://...:...@app.getsentry.com/...')
>>
>> app = Sentry(app, client=client)
>>
>>
>> This way client is configured on init and captureException works
>> automatically.
>>
>>
>>
>>
>> Friday, March 18, 2016 at 1:26:39 AM UTC+1, Zsolt Ero wrote:
>>>
>>> Thanks, I see. I believe this way I do not need the .ini part, do I?
>>>
>>> On Thursday, March 17, 2016 at 3:40:28 AM UTC+1, Jonathan Vanasco wrote:
>>>>
>>>>
>>>>
>>>> On Wednesday, March 16, 2016 at 9:36:44 PM UTC-4, Zsolt Ero wrote:
>>>>>
>>>>> David Cramer from Sentry replied to me that if Sentry is used with the
>>>>> middleware, then it should automatically receive the WSGI context:
>>>>> from sentry.middleware import Sentry
>>>>>
>>>>> application = Sentry(application, client=Client(dsn, ...))
>>>>>
>>>>> My problem is that in Pyramid I have no idea where could I get an
>>>>> application, or if this would work at all.
>>>>
>>>>
>>>> That looks like the initial app setup in your `project/__init__.py`
>>>>
>>>> `application` would be what is returned from config.make_wsgi_app()
>>>>
>>>> Some people do "return config.make_wsgi_app()"
>>>>
>>>> Others prefer "app = config.make_wsgi_app()", then wrap it in middleware
>>>>
>>>>
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