It's been very enlightening! Thank you very much.

Cheers,
Jerry

On Jan 28, 1:13 pm, Dalius Dobravolskas
<[EMAIL PROTECTED]> wrote:
> jerryji wrote:
> > Dear Pyloners,
>
> > Greatly appreciated if someone can shed some light on how to return a
> > byte stream from my controller.
>
> > For example, I want /image/123 to return an image so that it could be
> > referenced in another page as <img src="/image/123" alt="123" />
>
> > (similar discussion did appear before --
> >http://groups.google.com/group/pylons-discuss/msg/f87e2754e6004cb9
> > but doesn't seem to have an answer...)
>
> I use following:
>
> class JpegFileApp(DataApp):
>     """ Jpeg file serving. """
>
>     def __init__(self, filename, content, **kwargs):
>         self.filename = filename
>         kwargs['content_type'] = 'image/jpeg'
>         DataApp.__init__(self, content, None, **kwargs)
>         self.content_disposition(filename=filename)
>
>     def guess_type(self):
>         return 'image/jpeg'
> ...
> # Somewhere in your controller
>     def cover(self, id):
>        ...
>             app = JpegFileApp(id, image_bytes)
>             return app(request.environ, self.start_response)
>
> Technically you can return image as string and set proper Content-type
> in response.headers. E.g:
>
> response.headers['Content-type'] = 'image/jpeg'
> return image_bytes
>
> but it was very slow for me. Not sure why.
>
> Regards,
> Dalius
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