Much appreciated the response guys. However could somebody explain to
me the paginate.Page api.

Note sure what is acceptable to populate this api and the errors from
the debugger are a wee'  bit unclear on what the culprit is
and why.

However again thanks in advance.

Garyc

On Oct 11, 3:32 pm, Gael Pasgrimaud <[email protected]> wrote:
> On Sun, Oct 11, 2009 at 10:23 PM, Jason S. <[email protected]> wrote:
>
> > The query() and filter() functions both return query objects, not
> > result lists. This is very useful because you can chain together
> > multiple filters, order_bys, etc, but at the end you need to call .all
> > () to get a list (or .first() to get one object)
>
> Well, yes. But paginate.Page is supposed to work with query objects.
>
> I don't see the reason why it does not work for Garyc. The code
> snippet seems correct.
>
> --
> Gael
>
>
>
> > On Oct 11, 1:48 pm, gazza <[email protected]> wrote:
> >> Hello,
>
> >> I am seeing a problem when attempting to use the paginator.
>
> >> records= meta.Session.query(model.A).filter(mddel.A.tag==id)
>
> >> c.paginator = paginate.Page(
> >>                  records,
> >>                  page=int(request.params.get('page',1)),
> >>                  items_per_page =2,
> >> )
>
> >> I am seeing the error:
>
> >> Sorry yor collection type is not supported by the paginate module, You
> >> can either provide a list, a tuple, and SQLAlchemy 0.4 select object
> >> etc.
>
> >> The line its complaining on is "items_per_page".
>
> >> If somebody could be kind enough to enlighten me on the problem that
> >> would be great.
>
> >> Thanks,
> >> Garyc- Hide quoted text -
>
> - Show quoted text -
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