On Mon, 2012-01-09 at 13:51 -0800, Martin Aspeli wrote:
> Hi,
>
> I have a hybrid traversal use case with a route like:
>
> config.add_route('api', '/api/*traverse')
>
> I'd like to be able to generate a URL to a traversed-to resource, but
> request.resource_url() and request.route_url() don't work. I can do
> this:
>
> def api_resource_path(context, request):
> return
> request.current_route_path(traverse=urllib.unquote(resource_path(context)
> [1:]))
>
> That seems quite cumbersome, though. Is there a better API?
No, I'm afraid not. You could maybe work around the edges by something
like doing:
from pyramid.traversal import resource_path_tuple
request.current_route_path(traverse=resource_path_tuple(context)[1:])
- C
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