It's undefined. I'd suggest setting something in registry.settings and
using it if it exists.
On Tue, 2013-07-23 at 01:30 -0700, Robert Forkel wrote:
> Hi all,
> I just came across the same problem as OP: How do I determine the
> "application" package from an includeme function. I found the two
> attributes "package" and "package_name" of the Configurator object and
> think this is what I want. But since these are not documented as
> public API, is it safe to access them? Or may this change with any new
> pyramid version?
> best
> robert
>
> On Tuesday, September 18, 2012 3:57:21 PM UTC+2, askel wrote:
> I'm developing renderer library for Pyramid framework. It's
> just kind
> of adapter to use existing template engine in Pyramid
> applications.
> The library is using asset specs for template names. And I'd
> like it
> to use application package name in case asset spec is missing
> package
> part. Originally, I used caller_package
>
> from pyramid.path import caller_package, AssetResolver
>
> def includeme(config):
> package = caller_package(3)
> resolver = AssetResolver(package)
>
> While that worked for "imperative" configuration method (by
> calling
> config.include('my.library.package')), it did not work for
> "declarative" one (via pyramid.includes in INI file).
>
> I changed it to the following:
>
> def includeme(config):
> package = config.registry.__name__
> resolver = AssetResolver(package)
>
> And this way it works for both configuration methods. But I'm
> afraid
> that I'm using undocumented implementation details and that
> could stop
> working in the future.
>
> Is there any "official" way to determine application package
> name?
>
> - Alex K
>
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