Hi,
you may use peppercorn for this purpose :
import peppercorn
controls = request.params.items()
values = peppercorn.parse(controls)
try:
appstruct = schema.deserialize(values)
except colander.Invalid as e:
logger.exception(u"An error occured")
Hope this help,
Regards
Gaston
Le 08/06/2016 à 13:15, Andrius Kulbis a écrit :
> I started using colander in my pyramid project. Created a simple data
> model mapping using colander
> |
> classDataModel(colander.MappingSchema): user_count
> =colander.SchemaNode(colander.Integer()) expiration_date
> =colander.SchemaNode(colander.Date()) comment
> =colander.SchemaNode(colander.String())
> |
>
> How can I pass submited form data to this mapping ir order to validate
> it without using deform? Is it possible to iterate over a validation
> errors?
>
> |
> model =DataModel()
>
> if'submit'request.POST:
> form_data =request.POST.items()
> ???
> |
>
>
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