Just to expand on Theron's suggestion a bit more: there is not a general
solution to the problem because Pyramid's routing system is flexible enough
that it's not easy to tell which view will be invoked for a particular
request without actually executing the request. If you know what permission
the user will need and what context the user will have then you can use
request.has_permission(permission, context=context). If this isn't
satisfactory then you'll have to come up with something outside of the
per-request security system Pyramid provides to know what the user "could"
have access to.

- Michael

On Wed, Feb 20, 2019 at 10:48 AM Theron Luhn <[email protected]> wrote:

> Check out request.has_permission:
> https://docs.pylonsproject.org/projects/pyramid/en/latest/api/request.html#pyramid.request.Request.has_permission
>
> — Theron
>
>
>
> On Feb 20, 2019, at 3:10 AM, Thijs <[email protected]> wrote:
>
> In a view I want to return a few hyperlinks to other views. However, I
> don't want to present users with links to views they have no permission
> for. Is there any way to check if a user has access to a certain view so I
> can omit the links to denied views?
>
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