Hi Ramiro,
A bit of linear algebra wouldn't hurt... :p
In python:
def vsub(a,b): return a[0]-b[0], a[1]-b[1], a[2]-b[2]
def dot(a,b): return a[0]*b[0]+a[1]*b[1]+a[2]*b[2]
def svmul(s,a): return s*a[0], s*a[1], s*a[2]
def normalize(a): return svmul(1/math.sqrt(dot(a,a)),a)
def cross(a,b): return a[1]*b[2]-a[2]*b[1], a[2]*b[0]-a[0]*b[2],
a[0]*b[1]-a[1]*b[0]
a = cmd.get_model('r. phe and i. ##RESIDUE1## and n. cg,ce1,ce2').atom
a = [ i.coord for i in a ]
b = cmd.get_model('r. phe and i. ##RESIDUE2## and n. cg,ce1,ce2').atom
b = [ i.coord for i in b ]
na = normalize(cross(vsub(a[1],a[0]),vsub(a[2],a[0])))
nb = normalize(cross(vsub(b[1],b[0]),vsub(b[2],b[0])))
angle = math.acos(dot(na,nb))
print angle
###
Haven't tested it, and there may be more efficient ways of getting the
coordinates. If you run into problems like this more often, it's
likely that you should pick up on algebra and programming... :)
Have fun,
Tsjerk
On Thu, Sep 23, 2010 at 12:19 PM, Ramiro Téllez Sanz
<urcind...@gmail.com> wrote:
> Thanks for your kind help, Tsjerk.
>
>> Hi Ramiro,
>>
>> Assuming your rings are nicely planar, and representing the ring as:
>>
>> 1-2-3
>> | |
>> 6-5-4
>>
>> you can get the plane normal vector as the vector cross product from
>> (3)-(1) and (5)-(1).
>
> OK. But I just started to use pymol. Which are the commands to do so?
> I know how to get the coordinates of a selected atom, but need the pymol
> commands to treat the data:
> a) How to create the vectors from 1->3 and from 1->5
> b) How to treat the vectors to perform the vector cross product
>
>> Doing so for both rings gives you the two normal vectors. The angle
>> then follows from the dot product of the (normalized) normal vectors:
>>
>> angle = acos(n1 . n2)
>
> Again, I would need the commands to:
> c) Normalize the vectors (how to set their modules = 1)
>
> I also guess n1 and n2 represent the normalized vectors, don't they? So
> this command is very clear :)
>
>> It becomes a bit more elaborate if the planes are not planar :)
>>
>> Hope it helps,
>>
>> Tsjerk
>
> Again, thanks very much in advance for your kind help.
>
>> On Thu, Sep 23, 2010 at 10:53 AM, Ramiro Téllez Sanz
>> <urcind...@gmail.com> wrote:
>>>
>>> Hi everyone and thanks for reading this!
>>>
>>> I am interested in measuring the angle between aromatic ring planes.
>>> Is there any easy way/script to do it?
>>>
>>> One way that came to my mind is creating a pseudoatom representing the
>>> centroid for each ring (I already know how to do that), then drawing two
>>> lines perpendicularly to the planes from both centroids, and finally
>>> measuring the angle between the lines. Will that be possible? How could
>>> this be done?
>>>
>>> Is there any other way? I'm completely clueless. Any help will be
>>> greatly appreciated.
>>>
>>> Thanks in advance,
>>>
>>> Ramiro Tellez Sanz
>>> Dept. Physical Chemistry
>>> University of Almeria
>>> Spain
>>>
>>>
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>>
>>
>
>
--
Tsjerk A. Wassenaar, Ph.D.
post-doctoral researcher
Molecular Dynamics Group
Groningen Institute for Biomolecular Research and Biotechnology /
University of Groningen
The Netherlands
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