On 2007-10-16, Sergio Jovani Guzmán wrote:
> Hi all!
>
> I am learning PyQt and I have a question.
>
> I have two classes, one for each widget:
>
> ==================
> class Main(QMainWindow):
> def __init__(self):
> QMainWindow.__init__(self)
> loadUi("frmmain.ui", self)
>
> class Conectar(QDialog):
>
> def __init__(self):
> QDialog.__init__(self)
> loadUi("frmconectar.ui", self)
> =====================
>
> My question is, how can I call and show a widget from other with parent?
>
> For example, open Conectar() window from Main() window?
>
> Many thanks!
You need a method in your Main() class, something like this (untested):
def runConectar(self):
conectar = Conectar(self)
if conectar.exec():
pass # User clicked OK
And in the Main() __init__ method, assuming you have an action called
runConectarAction:
self.connect(runConectarAction, SIGNAL("triggered()"),
self.runConectar)
--
Mark Summerfield, Qtrac Ltd., www.qtrac.eu
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