A couple of (also untested) tweaks?
Mark Summerfield wrote:
On 2007-10-16, Sergio Jovani Guzmán wrote:
Hi all!
I am learning PyQt and I have a question.
I have two classes, one for each widget:
==================
class Main(QMainWindow):
def __init__(self):
QMainWindow.__init__(self)
loadUi("frmmain.ui", self)
class Conectar(QDialog):
def __init__(self):
QDialog.__init__(self)
loadUi("frmconectar.ui", self)
=====================
My question is, how can I call and show a widget from other with parent?
For example, open Conectar() window from Main() window?
Many thanks!
You need a method in your Main() class, something like this (untested):
def runConectar(self):
conectar = Conectar(self)
if conectar.exec():
if conectar.exec_():
pass # User clicked OK
And in the Main() __init__ method, assuming you have an action called
runConectarAction:
self.connect(runConectarAction, SIGNAL("triggered()"),
self.runConectar)
self.connect(runConectarAction, SIGNAL("triggered(bool)"),
self.runConectar)
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